Exam technique · Chemistry · 7 min read
IB Chemistry Paper 2 tips: calculations, explanations and mechanisms that earn the marks
How to set out working so every method mark is visible, how error carried forward protects you, and how to write explanations at the level of particles.
On this page
- What does Chemistry Paper 2 look like at SL and HL?
- How should you lay out a calculation to earn method marks?
- How do you make error carried forward work for you?
- How do you write an "explain" answer at particle level?
- How do you draw structures and mechanisms that score?
- How should you use the data booklet in Paper 2?
- How should you pace Paper 2?
- What changes between SL and HL?
IB Chemistry Paper 2 rewards working you can see. Marks are split between method and answer, so a calculation laid out step by step can earn most of its marks even with a slip, and a bare final number earns nothing if it is wrong. The other big scorers are explanations written in terms of particles, structures and mechanisms drawn to the conventions, and pacing that gets you to the last question. This guide covers each, with original worked examples.
What does Chemistry Paper 2 look like at SL and HL?
| Item | SL | HL |
|---|---|---|
| Time | 1 h 30 min | 2 h 30 min |
| Marks | 50 | 90 |
| Weight | 44% | 44% |
| Minutes per mark | 1.8 | about 1.7 |
| Content | SL syllabus | SL and additional HL syllabus |
Both levels contain short-answer and extended-response questions, and calculators and a clean data booklet are allowed. One number to get right: HL Chemistry Paper 2 is out of 90, not 80 as in HL Biology, so don't borrow timing plans from a Biology friend. The subject guide does not divide the Chemistry paper into named sections, so look at a specimen or recent paper with your teacher to see the layout. For the whole exam structure, see what the Chemistry exams look like now.
How should you lay out a calculation to earn method marks?
Mark schemes usually award marks for intermediate steps (a correct amount in mol, a correct substitution) as well as for the final answer. Make every step visible:
- Write the equation or relationship you are using (n = m ÷ M, pV = nRT).
- Convert units first, on their own line.
- Substitute, with units.
- Write each intermediate value, keeping extra digits in the calculator.
- Give the final answer with units and sensible significant figures, set apart so the examiner can find it.
Worked example 1: molar mass from gas data
Original example written for this guide; it is not an IB question.
0.500 g of a volatile liquid is vaporised. The vapour occupies 155 cm3 at 373 K and 101 kPa. Calculate the molar mass, assuming ideal behaviour (R = 8.31 J K−1 mol−1).
Loses marks n = 101 000 × 0.155 ÷ (8.31 × 373) = 5.05 mol; M = 0.500 ÷ 5.05 = 0.099 g mol−1.
Earns marks p = 1.01 × 105 Pa; V = 155 × 10−6 m3 = 1.55 × 10−4 m3.
n = pV ÷ RT = (1.01 × 105 × 1.55 × 10−4) ÷ (8.31 × 373) = 5.05 × 10−3 mol.
M = m ÷ n = 0.500 ÷ 5.05 × 10−3 = 99.0 g mol−1.
The first answer used Pa with dm3, so it is out by a factor of 1000; a molar mass below 1 g mol−1 is impossible and should have been a warning. The second makes the unit conversion its own line, which is where the method mark sits. (Using kPa with dm3 gives the same correct answer, because kPa × dm3 = J; what fails is mixing Pa with dm3.)
How do you make error carried forward work for you?
Error carried forward (ECF) lets a later part earn its marks when you use your own earlier wrong value correctly, so one slip costs one mark instead of a whole chain. The full explanation, with a worked titration chain and the limits on when ECF applies, is in IB mark schemes explained. In Chemistry Paper 2 it comes down to three habits:
- Put each intermediate value on its own line, with its label and units (n(HCl), then n(Na2CO3), then the concentration), so the examiner can find the value you carried forward.
- Use your own earlier answer, even if you doubt it. Switching to a "nicer" number you guessed breaks the chain the examiner is trying to follow.
- If you couldn't get an earlier value at all, state an assumed one ("assuming n = 2.00 × 10−3 mol") and carry on. Correct method on it may still earn marks; a blank cannot.
How do you write an "explain" answer at particle level?
Most Chemistry "explain" marks go to three moves: name the particles, name the interaction or energy change involved, and link it to the observation. Count the marks and make sure each move is a separate statement.
Worked example 2: comparing boiling points
Original example written for this guide; it is not an IB question.
Explain why ethanol (C2H5OH, boiling point 78 °C) has a much higher boiling point than propane (C3H8, −42 °C), although they have similar molar masses. [3]
Loses marks Ethanol has stronger bonds than propane, so it needs more energy to boil.
Earns marks Both have London dispersion forces of similar strength, because their molar masses and numbers of electrons are similar (46 and 44 g mol−1). Ethanol molecules also form hydrogen bonds with each other, through the H on the O–H group and a lone pair on the O of a neighbouring molecule. Hydrogen bonds are stronger than London forces, so more energy is needed to separate ethanol molecules.
"Stronger bonds" loses the marks twice: it doesn't say which forces, and it implies covalent bonds break on boiling. The same structure works for rates (collision frequency and energy relative to Ea), conductivity (mobile ions or delocalised electrons) and equilibrium shifts. Our list of common IB Chemistry mistakes has more wrong-versus-right pairs.
For extended responses worth more marks, plan in the margin first: one short note per mark, in the order you will write them. Clear numbered points are fine if each is a full statement; the examiner is looking for distinct, correct chemistry, not style.
How do you draw structures and mechanisms that score?
Structures
- Lewis formulas show every lone pair, not just the bonding pairs: one on N in NH3, two on O in H2O, three on Cl in HCl.
- State the shape and the angle together: CH4 tetrahedral, 109.5°; NH3 trigonal pyramidal, about 107°; H2O bent, about 104.5°. Then say why: lone pairs repel more than bonding pairs.
- A full structural formula shows every bond, including the O–H in an alcohol and each C–H. Writing CH3 is a condensed formula, so check which one the question asks for.
- Stereoisomers need the 3D or cis/trans arrangement actually drawn, not just named.
Mechanisms
Draw each mechanism your level requires the same way every time, ticking off this list:
- Every curly arrow starts at a lone pair or a bond and ends where the electron pair goes.
- The lone pair on the nucleophile is drawn, and so is the charge on any ion.
- Partial charges (δ+, δ−) are shown on the polar bond being attacked.
- Where a transition state or intermediate is required, it is drawn with its charge (in square brackets for a transition state).
- The products, including the leaving group, are shown.
A mechanism with every arrow correct but no products, or with an arrow starting from the minus sign of OH− rather than its lone pair, can lose marks that were otherwise yours.
How should you use the data booklet in Paper 2?
- Know the layout before the exam. Practise every past question with the same edition you will be given, so finding a bond enthalpy or a constant takes seconds.
- Quote the value you used in your working ("C–H = 414 kJ mol−1"). It shows the examiner where the number came from.
- Use the question's values over the booklet's whenever the question supplies them.
- Know what isn't there. Relationships you are expected to know, and the reasoning behind every value, still have to come from you.
How should you pace Paper 2?
At 1.8 minutes per mark (SL) or about 1.7 (HL), a 6-mark question deserves around 10 minutes and a 1-mark "state" deserves a few seconds. Three habits:
- Glance through the whole paper first (a minute or two) so the hardest-looking question doesn't ambush you at the end.
- Set checkpoints. At HL, aim to be about one third of the way through the marks after 50 minutes, two thirds after 100.
- Move on when stuck, leaving space to come back. An unfinished calculation with working shown can still earn method marks; a blank cannot.
Our guide to time management in IB exams covers recovery when you fall behind, and the Paper 1A guide covers the multiple-choice half of the course.
What changes between SL and HL?
The skills are the same; the scale and content differ. HL Paper 2 is 60 minutes longer and worth 40 more marks, and it draws on the additional HL content too: for example, Reactivity 1.4 (entropy and spontaneity, which is HL only) and the extended acid–base and electrochemistry calculations in Reactivity 3.1 and 3.2. Both levels give Paper 2 the same 44% weight. If you are HL, practise sustained calculation chains, because a long paper rewards stamina as much as speed.
Questions students ask
How long is IB Chemistry Paper 2?
1 hour 30 minutes for 50 marks at SL, and 2 hours 30 minutes for 90 marks at HL. At both levels it is worth 44% of the grade and contains short-answer and extended-response questions.
If I get part (a) wrong, do I lose the marks for the later parts?
Not necessarily. Where the mark scheme allows error carried forward, a later part can still earn its marks if you used your earlier (wrong) answer with the correct method. This only works if your working is written down, so always show it.
Can I use a calculator and the data booklet in Chemistry Paper 2?
Yes, at both SL and HL. Calculators are permitted on all papers in the current course, and every candidate must have a clean copy of the Chemistry data booklet for Paper 1 and Paper 2.
Try one: Chemistry
2.00 g of hydrated magnesium sulfate, MgSO4·xH2O, is heated to constant mass. The anhydrous MgSO4 left has a mass of 0.977 g. Determine the value of x. (M: MgSO4 = 120.38 g mol−1; H2O = 18.02 g mol−1)
[3 marks]Show the answer and why
- Mass of water lost = 2.00 − 0.977 = 1.023 g
- n(MgSO4) = 0.977 ÷ 120.38 = 8.12 × 10−3 mol and n(H2O) = 1.023 ÷ 18.02 = 5.68 × 10−2 mol
- Ratio n(H2O) ÷ n(MgSO4) = 7.0, so x = 7
The ratio comes out at 6.99, which rounds to the whole number 7: magnesium sulfate heptahydrate. If you slipped on the mass of water but then divided correctly, the third mark could still be available as error carried forward, which is why each step is written on its own line.